(5x-4)(x^2-3x+1)=

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Solution for (5x-4)(x^2-3x+1)= equation: 


Simplifying
(5x + -4)(x2 + -3x + 1) = 0

Reorder the terms:
(-4 + 5x)(x2 + -3x + 1) = 0

Reorder the terms:
(-4 + 5x)(1 + -3x + x2) = 0

Multiply (-4 + 5x) * (1 + -3x + x2)
(-4(1 + -3x + x2) + 5x * (1 + -3x + x2)) = 0
((1 * -4 + -3x * -4 + x2 * -4) + 5x * (1 + -3x + x2)) = 0
((-4 + 12x + -4x2) + 5x * (1 + -3x + x2)) = 0
(-4 + 12x + -4x2 + (1 * 5x + -3x * 5x + x2 * 5x)) = 0
(-4 + 12x + -4x2 + (5x + -15x2 + 5x3)) = 0

Reorder the terms:
(-4 + 12x + 5x + -4x2 + -15x2 + 5x3) = 0

Combine like terms: 12x + 5x = 17x
(-4 + 17x + -4x2 + -15x2 + 5x3) = 0

Combine like terms: -4x2 + -15x2 = -19x2
(-4 + 17x + -19x2 + 5x3) = 0

Solving
-4 + 17x + -19x2 + 5x3 = 0

Solving for variable 'x'.

The solution to this equation could not be determined.

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